Using Python-Oauth2 To Access OAuth Protected Resources

Posted June 13, 2010 * Comments(4)

Most of the examples I found for python-oauth2 show how to use the library to request and approve tokens, but not how to use the access token to access a protected resource (ie. how to actually make a call to the service you’re trying to access). Here’s an example:


import oauth2 as oauth
consumer = oauth.Consumer('consumer-key-here','consumer-secret-here')
token = oauth.Token('access-key-here','access-key-secret-here')
client = oauth.Client(consumer, token)
response = client.request('http://someservice.com/api/something/')

And here’s how you make a POST call:


import urllib
response, content = myclient.request("http://someservice.com/api/something/", \
    method="POST", body=urllib.urlencode({'name': 'value', 'another_name': 'another value'}) )

4 Comments so far

  1. Rich on April 4th, 2011

    Thanks so much… it’s amazing that ten months after your post, python-oauth2 still doesn’t provide an example of how to access a protected resource!

  2. rasadacrea on August 30th, 2011

    Excellent post complementing usage of python-oauth2 to post tweets

    postapi = ‘http://api.twitter.com/1/statuses/update.json’
    def oauth_post(postapi, ckey, csecret, akey, asecret, status):
    consumer = oauth.Consumer(key=ckey, secret=csecret)
    token = oauth.Token(key=akey, secret=asecret)
    client = oauth.Client(consumer, token)
    resp, content = client.request(
    postapi,
    method
    body = urllib.urlencode({’status’: status, ‘wrap_links’: True}),
    #headers=http_headers,
    #force_auth_header=True
    )
    return resp, content

  3. rasadacrea on August 30th, 2011

    Excellent post complementing usage of python-oauth2 to post tweets

    postapi = ‘http://api.twitter.com/1/statuses/update.json’
    def oauth_post(postapi, status, ckey, csecret, akey, asecret):
    consumer = oauth.Consumer(key=ckey, secret=csecret)
    token = oauth.Token(key=akey, secret=asecret)
    client = oauth.Client(consumer, token)
    resp, content = client.request(
    postapi,
    method=’POST’,
    body = urllib.urlencode({’status’: status, ‘wrap_links’: True}),
    )
    return resp, content

  4. Greg on December 22nd, 2011

    Thank you! You saved me!

    And for those dealing with shitty APIs (…) that return a token key (but not a token secret), try passing the received token as the token key, and an empty string as the token secret… That was a great hour wasted…! ;-)

    Cheer

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